How to Divide Square Roots

Co-authored by David Jia

Last Updated: October 9, 2022 References

Dividing square roots is essentially simplifying a fraction. Of course, the presence of square roots makes the process a little more complicated, but certain rules allow us to work with fractions in a relatively simple way. The key thing to remember is that you must divide coefficients by coefficients, and radicands by radicands. You can also never have a square root in a denominator.

Method 1

Method 1 of 4:

Dividing Radicands

1
Set up a fraction. If your expression is not already set up like a fraction, rewrite it this way. This makes it easier to follow all the necessary steps when dividing by a square root. Remember that a fraction bar is also a division bar.^{[1]
X
Research source}
- For example, if you are calculating ${\sqrt {144}}\div {\sqrt {36}}$ , rewrite the problem like this: ${\frac {\sqrt {144}}{\sqrt {36}}}$ .
2
Use one radical sign. If your problem has a square root in the numerator and denominator, you can place both radicands under one radical sign.^{[2]
X
Research source} (A radicand is a number under a radical, or square root, sign.) This will simplify the simplifying process.
- For example, ${\frac {\sqrt {144}}{\sqrt {36}}}$ can be rewritten as ${\sqrt {\frac {144}{36}}}$ .
Advertisement
3
Divide the radicands. Divide the numbers as you would any whole number. Make sure to place their quotient under a new radical sign.^{[3]
X
Research source}
- For example, ${\frac {144}{36}}=4$ , so ${\sqrt {\frac {144}{36}}}={\sqrt {4}}$ .
4
Simplify, if necessary. If the radicand is a perfect square, or if one of its factors is a perfect square, you need to simplify the expression. A perfect square is the product of a whole number multiplied by itself.^{[4]
X
Research source} For example, 25 is a perfect square, since $5\times 5=25$ $5\times 5=25$ .
- For example, 4 is a perfect square, since $2\times 2=4$ . Thus:
  ${\sqrt {4}}$
  $={\sqrt {2\times 2}}$
  $=2$
  So, ${\frac {\sqrt {144}}{\sqrt {36}}}={\sqrt {4}}=2$ .

Method 2

Method 2 of 4:

Factoring Radicands

1
Express the problem as a fraction. You will likely already see the expression written this way. If not, change it. Solving the problem as a fraction makes it easier to follow all the necessary steps, especially when factoring the square roots. Recall that a fraction bar is also a division bar.^{[5]
X
Research source}
- For example, if you are calculating ${\sqrt {8}}\div {\sqrt {36}}$ , rewrite the problem like this: ${\frac {\sqrt {8}}{\sqrt {36}}}$ .
2
Factor each radicand. Factor the number as you would any whole number. Keep the factors under the radical signs.^{[6]
X
Research source}
- For example:
  ${\frac {\sqrt {8}}{\sqrt {36}}}={\frac {\sqrt {2\times 2\times 2}}{\sqrt {6\times 6}}}$
3
Simplify the numerator and denominator of the fraction. To simplify a square root, pull out any factors that make a perfect square. A perfect square is the result of a whole number multiplied by itself.^{[7]
X
Research source} The factor will now become a coefficient outside of the square root.
- For example:
  ${\frac {\sqrt {{\cancel {2\times 2\times }}2}}{\sqrt {\cancel {6\times 6}}}}$
  ${\frac {2{\sqrt {2}}}{6}}$
  So, ${\frac {\sqrt {8}}{\sqrt {36}}}={\frac {2{\sqrt {2}}}{6}}$
4
Rationalize the denominator, if necessary. As a rule, an expression cannot have a square root in the denominator. If your fraction has a square root in the denominator, you need to rationalize it. This means to cancel out the square root in the denominator. To do this, multiply the numerator and denominator of the fraction by the square root you need to cancel.^{[8]
X
Research source}
- For example, if your expression is ${\frac {6{\sqrt {2}}}{\sqrt {3}}}$ , you need to multiply the numerator and denominator by ${\sqrt {3}}$ to cancel the square root in the denominator:
  ${\frac {6{\sqrt {2}}}{\sqrt {3}}}\times {\frac {\sqrt {3}}{\sqrt {3}}}$
  $={\frac {6{\sqrt {2}}\times {\sqrt {3}}}{{\sqrt {3}}\times {\sqrt {3}}}}$
  $={\frac {6{\sqrt {6}}}{\sqrt {9}}}$
  $={\frac {6{\sqrt {6}}}{3}}$ .
5
Simplify further, if necessary. Sometimes you will be left with coefficients that can be simplified, or reduced. Simplify the whole numbers in the numerator and denominator as you would simplify any fraction.^{[9]
X
Research source}
- For example, ${\frac {2}{6}}$ reduces to ${\frac {1}{3}}$ , so ${\frac {2{\sqrt {2}}}{6}}$ reduces to ${\frac {1{\sqrt {2}}}{3}}$ , or simply ${\frac {\sqrt {2}}{3}}$ .

Method 3

Method 3 of 4:

Dividing Square Roots with Coefficients

1
Simplify the coefficients. These are the numbers outside of the radical sign. To simplify them, divide or reduce, ignoring the square roots for now.^{[10]
X
Research source}
- For example, if you are calculating ${\frac {4{\sqrt {32}}}{6{\sqrt {16}}}}$ , you would first simplify ${\frac {4}{6}}$ . The numerator and denominator can both be divided by a factor of 2. So, you can reduce: ${\frac {4}{6}}={\frac {2}{3}}$ .
2
Simplify the square roots. If the numerator is evenly divisible by the denominator, simply divide the radicands. If not, simplify each square root as you would any square root.^{[11]
X
Research source}
- For example, since 32 is evenly divisible by 16, you can divide the square roots: ${\sqrt {\frac {32}{16}}}={\sqrt {2}}$ .
3
Multiply the simplified coefficient(s) by the simplified square root. Remember that you cannot have a square root in a denominator, so when multiplying a fraction by a square root, place the square root in the numerator.^{[12]
X
Research source}
- For example, ${\frac {2}{3}}\times {\sqrt {2}}={\frac {2{\sqrt {2}}}{3}}$ .
4
Cancel the square root in the denominator, if necessary. This is called rationalizing the denominator. As a rule, an expression cannot have a square root in the denominator. To rationalize the denominator, multiply the numerator and denominator by the square root you need to cancel.^{[13]
X
Research source}
- For example, if your expression is ${\frac {4{\sqrt {3}}}{2{\sqrt {7}}}}$ , you need to multiply the numerator and denominator by ${\sqrt {7}}$ to cancel the square root in the denominator:
  ${\frac {4{\sqrt {3}}}{\sqrt {7}}}\times {\frac {\sqrt {7}}{\sqrt {7}}}$
  $={\frac {4{\sqrt {3}}\times {\sqrt {7}}}{{\sqrt {7}}\times {\sqrt {7}}}}$
  $={\frac {4{\sqrt {21}}}{\sqrt {49}}}$
  $={\frac {4{\sqrt {21}}}{7}}$

Method 4

Method 4 of 4:

Dividing by a Binomial with a Square Root

1
Determine that you have a binomial in the denominator. The denominator will be the number in the problem you are dividing by. A binomial is a two-termed polynomial.^{[14]
X
Research source} This method only applies to division of square roots involving a binomial.
- For example, if you are calculating ${\frac {1}{5+{\sqrt {2}}}}$ , you have a binomial in the denominator, since $5+{\sqrt {2}}$ is a two-termed polynomial.
2
Find the conjugate of the binomial. Conjugate pairs are binomials that have the same terms, but opposite operations.^{[15]
X
Research source} Using a conjugate pair will allow you to cancel the square root in the denominator.
- For example, $5+{\sqrt {2}}$ and $5-{\sqrt {2}}$ are conjugate pairs, since they have the same terms but opposite operations.
3
Multiply the numerator and denominator by the denominator’s conjugate. Doing this will allow you to cancel the square root, because the product of a conjugate pair is the difference of the square of each term in the binomial.^{[16]
X
Research source} That is, $(a-b)(a+b)=a^{2}-b^{2}$ $(a-b)(a+b)=a^{{2}}-b^{{2}}$ .
- For example:
  ${\frac {1}{5+{\sqrt {2}}}}$
  $={\frac {1(5-{\sqrt {2}})}{(5+{\sqrt {2}})(5-{\sqrt {2}})}}$
  $={\frac {5-{\sqrt {2}}}{(5^{2}-({\sqrt {2}})^{2}}}$
  $={\frac {5-{\sqrt {2}}}{25-2}}$
  $={\frac {5-{\sqrt {2}}}{23}}$
  Thus, ${\frac {1}{5+{\sqrt {2}}}}={\frac {5-{\sqrt {2}}}{23}}$ .

Community Q&A

Question

How can I divide root 5 by 5?

Donagan

Top Answerer

√5 / 5 cannot be rationalized, simplified, or reduced. All you could do is to divide √5 (2.236) by 5.
Question

How can divide 1 by sqrt*2?

Community Answer

You need to rationalize the denominator, since a denominator cannot have a square root. To do this, multiply the numerator and the denominator by sqrt*2: 1 x sqrt*2 = sqrt*2 sqrt*2 x sqrt*2 = 2. So it simplifies to sqrt*2/2.
Question

How do I divide root3/root3?

Donagan

Top Answerer

Anything (other than zero) divided by itself is 1.

Warnings

Never leave a radical in the denominator of a fraction, but instead simplify or rationalize it.

⧼thumbs_response⧽
Helpful 1 Not Helpful 0
Never put or leave a decimal or a mixed number in front of a radical, but instead change either to a fraction and simplify the entire expression.

⧼thumbs_response⧽
Helpful 1 Not Helpful 0
Never put a decimal into a fraction. That would be a fraction within a fraction.

⧼thumbs_response⧽
Helpful 1 Not Helpful 0
If your denominator includes any kind of addition or subtraction, then use a conjugate pair method to remove radical from the denominator.

⧼thumbs_response⧽
Helpful 1 Not Helpful 0